Here is my answer to the Q: and A: on page 546 is in terms of ATP.  This is the way I put it on the screen. Anyway you wish to answer the question is all right.

Q29.2: How does the net energy yield from the metabolism of 3 moles of glucose 6-phosphate through the pentose phosphate pathway to pyruvate compare to the yield of 3 moles of glucose 6-phosphate through glycolysis?

Ans29.2: The net energy yield from 3 moles of glucose 6-phosphate metabolized through the pentose phosphate pathway and then the last portion of the glycolytic pathway is 6 moles of NADPH, 3 moles of CO2, 5 moles of NADH, 8 moles of ATP, and 5 moles of pyruvate.  The energy yielding reactions follow:
Glucose-6-phosphate dehydrogenase: 3 NADPH or 7.5 ATP
6-phosphogluconate dehydrogenase: 3 NADPH or 7.5 ATP
Glyceraldehyde-3-phosphate dehydrogenase: 5 NADH or 12.5 ATP
Phosphoglycerate kinase: 5 ATP
Pyruvate kinase: 5 ATP
Total: 37.5 ATP
In contrast, the metabolism of 3 moles of glucose 6-phosphate through glycolysis is 6 moles of NADH, 9 moles of ATP, and 6 moles of pyruvate.  The energy yielding reactions follow:
Phosphofructokinase-1: -3 ATP
Glyceraldehyde-3-phosphate dehydrogenase: 6 NADH or 15 ATP
Phosphoglycerate kinase: 6 ATP
Pyruvate kinase: 6 ATP
An extra molecule of Pyruvate: 12.5 ATP*
Total: 36.5 ATP
*The extra pyruvate is worth if oxidized by the pyruvate dehydrogenase reaction and the TCA cycle.

So the equivalent of  37.5 ATP from PPP versus the equivalent of 36.5 ATP from glycolysis if the extra pyruvate is taken into account. You get, roughly, the same amount of energy from either pathway.